Binary Cipher
//Program to find roots of a quadratic equations
import java.util.*;
class Roots
{
public static void main(String args[])
{
int a,b,c,d,f=0;
Scanner scr=new Scanner(System.in);
System.out.println(“nEnter the values of a ,b ,c : “);
a=scr.nextInt();
b=scr.nextInt();
c=scr.nextInt();
d=(b*b)-(4*a*c);
if(d==0)
{
System.out.println(“Roots are real and Equal”);
f=1;
}
else if(d>0)
{
System.out.println(“Roots are real and UnEqual”);
f=1;
}
else
System.out.println(“Roots are imaginary”);
if(f==1)
{
float r1=(float)(-b+Math.sqrt(d))/(2*a);
float r2=(float)(-b-Math.sqrt(d))/(2*a);
System.out.println(“Roots are : “+r1+” ,”+r2);
}
}
}
Output:
Enter the values of a ,b ,c :
1
2
-3
Roots are real and UnEqual
Roots are : 1.0 ,-3.0
The Outpud should be like this right ?
Output: D:Lab>javac Quad.java
D:Lab>java Quad
Enter a, b & c values 3 2 1
The roots are complex & imaginary
r1=0.0+i0.47140452 r2=0.0-i0.47140452
can anyone help us
can you explain it clearly..
Let me know exact point you are missing, will be happy to clarify?